-16x^2+150x+5.8=0

Solution for -16x^2+150x+5.8=0 equation:

-16x^2+150x+5.8=0

a = -16; b = 150; c = +5.8;
Δ = b2-4ac
Δ = 1502-4·(-16)·5.8
Δ = 22871.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-\sqrt{22871.2}}{2*-16}=\frac{-150-\sqrt{22871.2}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+\sqrt{22871.2}}{2*-16}=\frac{-150+\sqrt{22871.2}}{-32}
$